Answer
Thermal energy is generated in the rod at a rate of $~~1.44\times 10^{-7}~W$
Work Step by Step
In part (b), we found that $i = 6.00\times 10^{-4}~A$
We can find the power in the loop:
$P = i^2~R$
$P = (6.00\times 10^{-4}~A)^2(0.400~\Omega)$
$P = 1.44\times 10^{-7}~W$
Thermal energy is generated in the rod at a rate of $~~1.44\times 10^{-7}~W$
