Answer
The magnitude of the induced emf is $~~0.60~V$
Work Step by Step
We can find the induced emf:
$\mathscr{E} = -\frac{d\Phi}{dt}$
$\mathscr{E} = -\frac{dA}{dt}~B$
$\mathscr{E} = -L~v~B$
$\mathscr{E} = -(0.10~m)(5.0~m/s)(1.2~T)$
$\mathscr{E} = -0.60~V$
The magnitude of the induced emf is $~~0.60~V$
