Answer
Thermal energy is being generated in the rod at a rate of $~~0.90~W$
Work Step by Step
In part (c), we found that the induced current is $1.5~A$
We can find the power generated in the rod:
$P = i^2~R = (1.5~A)^2(0.40~\Omega) = 0.90~W$
Thermal energy is being generated in the rod at a rate of $~~0.90~W$
