Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 441: 91a

Answer

$0.35$ Hz

Work Step by Step

We know that: $$T=2\pi \sqrt{\frac{l}{g}}$$ We also know that: $$f=\frac{1}{T}$$ Substituting the first equation into the second equation and simplifying: $$f=\frac{1}{T}=\frac{1}{2\pi} \sqrt{\frac{g}{l}}$$ $$=\frac{1}{2\pi}$$ Now substituting the values and solving: $$\sqrt{\frac{9.8m/s^2}{2.0m}}=0.35 Hz$$
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