Answer
$a_m=1.5\times 10^2\frac{m}{s^2}$
Work Step by Step
We can find the maximum acceleration using the formula:
$a_m=x_m\omega^2$
We also know that:
$\omega=\sqrt\frac{K}{m}$
So, $a_m=x_m(\sqrt\frac{K}{m})^2$
This can be written as:
$a_m=x_m\frac{K}{m}$
We plug in the known values in the above equation to obtain:
$a_m=0.30\frac{250}{0.50}=150=1.5\times 10^2\frac{m}{s^2}$
