Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 441: 83a

Answer

$K=1.23\times10^{3}\frac{N}{m}$

Work Step by Step

According to Hook's law, $F=Kx$ This can be rearranged as: $K=\frac{F}{x}$ In the given scenario, $F=w=mg$ Hence, $K=\frac{mg}{x}$ We plug in the known values to obtain: $K=\frac{15(9.8)}{0.12}=1225=1.225\times 10^3=1.23\times10^3\frac{N}{m}$
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