Answer
$15800$ $m/s^2$
Work Step by Step
First, we find the angular frequency:
$$\omega=2\pi f= 2\pi (1000Hz)=6280 s^{-1}$$
Then, we find the maximum amplitude:
$$a_{max}=A\omega ^2=(0.40 \times 10^{-3}m)(6280s)^2$$ $$=15800 m/s^2$$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 15 - Oscillations - Problems - Page 441: 86a
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