Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 441: 87a

Answer

$I=0.735kg.m^2$

Work Step by Step

The rotational inertia is given using the formula: $I=\frac{1}{2}mr^2$ We plug in the known values in this formula to obtain: $I=\frac{1}{2}(3.00)(0.700)^2=0.735kg.m^2$
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