Answer
$2.51$ m/s
Work Step by Step
First, we find the angular velocity:
$$ω=2πf=2π(1000Hz)=6280s^{-1}$$
Then, we find the maximum velocity as:
$$v_{max}=A\omega=(.00040m)(6280 s^{-1})$$ $$=2.51m/s$$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 15 - Oscillations - Problems - Page 441: 86b
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