Answer
$10x$
Work Step by Step
We know that:
$\omega=\sqrt\frac{K}{m}$
This can be written as:
$K=m\omega^2$
$K=(0.1)(10)^2=10\frac{N}{m}$
According to Hook's law;
$F=-Kx$
We plug in the known values to obtain:
$F=-10x$
Therefore, the magnitude is $10x$.
