Answer
$a_m=0.912\frac{cm}{s^2}$
Work Step by Step
The maximum acceleration can be determined as:
$a_m=x_m\omega^2$
We plug in the known values in the formula above to obtain:
$a_m=(0.37)(\frac{\pi}{2})^2$
$a_m=0.912\frac{cm}{s^2}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 15 - Oscillations - Problems - Page 441: 90g
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