Answer
$w=76N$
Work Step by Step
We know that,
$\omega=2{\pi}f$
$\omega=2{\pi}(2)=4\pi\frac{rad}{s}$
We also know that $\omega=\sqrt\frac{K}{m}$ which can be written as
$m=\frac{K}{\omega^2}$
Substituting the values into this formula and solving:
$m=\frac{1225}{4\pi^2}=7.76Kg$
Thus the weight of the package is;
$w=mg$
$w=(7.76)(9.8)=76N$
