Answer
$f=498Hz$
Work Step by Step
We know that,
$a=A{\omega^2}$
where $A$ and ${\omega}$ represent amplitude and angular frequency respectively.
This simplifies to:
${\omega}=\sqrt{\frac{a}{A}}$
For the given condition, $a=g$:
${\omega}=\sqrt{\frac{g}{A}}$
We plug in the known values to obtain:
${\omega}=\sqrt{\frac{9.8}{1\times 10^{-6}}}$
${\omega}=3130.5\frac{rad}{s}$
We also know that
$f=\frac{\omega}{2\pi}$
$f=\frac{3130.5}{2\times 3.1416}$
$f=498Hz$
