Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 436: 17b

Answer

$m=0.325Kg$

Work Step by Step

$'\omega'$ angular frequency and $'m'$ are related as follows $\omega=\sqrt\frac{K}{m}$ squaring both sides,we get $\omega^2=\frac{K}{m}$ $m=\frac{K}{\omega^2}$ put the values $m=\frac{400}{(35.07)^2}$ $m=0.325Kg$
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