Answer
$K=79.0\frac{N}{m}$
Work Step by Step
Spring constant $'K'$ can be calculated from the following formula:
$\omega=\sqrt\frac{K}{m}$
squaring both sides, we get
$\omega^2=\frac{K}{m}$
$K={\omega^2}m$
putting the values, we get
$K=(12.6)^2(0.500)$
$K=79.38\frac{N}{m}$
$K=79.0\frac{N}{m}$
