Answer
$$
2.2 \mathrm{Hz}
$$
Work Step by Step
Since $\omega=2 \pi f,$ and $x_{m}=0.050 \mathrm{m}$ is given, we find
$$
(2 \pi f)^{2} x_{m}=g \Rightarrow f=\frac{1}{2 \pi} \sqrt{\frac{g}{x_{m}}}=2.2 \mathrm{Hz}
$$
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