Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 436: 13e

Answer

$v_m=4.4\frac{m}{s}$

Work Step by Step

We know that $v_m=\omega{X_m}$ where $'v_m'$ represents maximum speed, similarly '$X_m'$ is the amplitude and $'\omega'$ is the angular frequency given that $X_m=35cm=\frac{35}{100}m=0.35m$ Now put the values in the first equation $v_m=(12.6)(0.35)=4.41 \frac{m}{s}$ or $v_m=4.4\frac{m}{s}$
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