Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 436: 6b

Answer

$0.0016m$

Work Step by Step

As maximum displacement means amplitude$A$,so we have to find $A$. Mathematically $V_{max}=A\omega$ or $A=\frac{V_{max}}{\omega}$ Put the values $A=\frac{1\times10^3}{628318.5}$ $A=0.0016m$
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