Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 436: 4a

Answer

$k = 1.29\times 10^5~N/m$

Work Step by Step

Each spring oscillates with a mass of $\frac{1450~kg}{4}$ which is $362.5~kg$ We can find the spring constant of each spring: $f = \frac{1}{2\pi}~\sqrt{\frac{k}{m}}$ $2\pi~f = \sqrt{\frac{k}{m}}$ $4\pi^2~f^2 = \frac{k}{m}$ $k = 4\pi^2~f^2~m$ $k = (4\pi^2)~(3.00~Hz)^2~(362.5~kg)$ $k = 1.29\times 10^5~N/m$
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