Answer
$$
0.25 \mathrm{m}
$$
Work Step by Step
Using Eq. $15-5$ and $T=1.0 \mathrm{s}$ , we have
$$
\left[\frac{2 \pi}{T}\right]^{2} x_{m}=g \Rightarrow x_{m}=\frac{g T^{2}}{4 \pi^{2}}=0.25 \mathrm{m}
$$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 15 - Oscillations - Problems - Page 436: 19a
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