Answer
$v_{max}=0.75\frac{m}{s}$
Work Step by Step
As $\omega=2\pi$$f$
We also know that
$v_{max}=A\omega$
Where $'A'$ represents Amplitude, and $'\omega'$ is the angular velocity
To find $'\omega'$, put the values in the first equation
$\omega=2\times3.14\times120$
$\omega=754\frac{rad}{s}$
Now we can find $'v_{max}'$ by putting the values
$v_{max}=(1mm)(754\frac{rad}{s})=0.754\frac{m}{s}$
or after rounded it off, we get
$v_{max}=0.75\frac{m}{s}$
