Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems - Page 48: 67


a) $4.17\hat{j}\ m/s$ b) $6.94 \ m/s^2$

Work Step by Step

In order to create the graph, graph all of the x-coordinates along with the corresponding y-coordinates that occur at the same point in time. This will create a sideways parabola, which starts at (0,0) and ends at (0,5). a) The key idea here is that the question asks for velocity, not speed. Thus, we find: $\vec{v}=\frac{5-0}{1.2}\hat{j}=4.17\hat{j}\ m/s$ b) The acceleration is centripetal, so we find: $a =\frac{v^2}{r}=\frac{4.17^2}{2.5}=6.94 \ m/s^2$
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