Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems: 36

Answer

Please see the work below.

Work Step by Step

We know that $t=\frac{x}{v}$ We plug in the known values to obtain: $t=\frac{23}{41}=0.561s$ And the height is $h=(\frac{1}{2})gt^2$ We plug in the known values to obtain: $h=(\frac{1}{2})(9.8)(0.561)^2=1.5m$
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