## Essential University Physics: Volume 1 (3rd Edition)

We know that $t=\frac{x}{v}$ We plug in the known values to obtain: $t=\frac{23}{41}=0.561s$ And the height is $h=(\frac{1}{2})gt^2$ We plug in the known values to obtain: $h=(\frac{1}{2})(9.8)(0.561)^2=1.5m$