Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems: 43

Answer

Please see the work below.

Work Step by Step

We know that $\omega=\frac{2\pi \frac{rad}{s}}{27days\times \frac{24hrs}{day}\times \frac{3600s}{hr}}=\times 10^{-6}\frac{rad}{s}$ $r=384.4Mm=3.844\times 10^8m$ $v=r\omega$ We plug in the known values to obtain: $v=(3.844\times 10^8)(2.7\times 10^{-6}\frac{rad}{s})=1035.3\frac{m}{s}$ We also know that $a=\frac{v^2}{r}$ We plug in the known values to obtain: $a=\frac{(1035.3)^2}{3.844\times 10^8}$ $a=2.8\times 10^{-3}\frac{m}{s^2}$
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