Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems: 62

Answer

Please see the work below.

Work Step by Step

We know that $t=\sqrt{\frac{2h}{g}}$ We plug in the known values to obtain: $t=\sqrt{\frac{(2)(1.9)}{9.8}}=0.623s$ Now we can find the horizontal speed as $v=\frac{x}{t}$ We plug in the known values to obtain: $v=\frac{4.5}{0.623}=7.2\frac{m}{s}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.