Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems: 40

Answer

Please see the work below.

Work Step by Step

We know that $v=350\frac{km}{h}=350\frac{Km\times 1000\frac{m}{Km}}{h\times 3600\frac{s}{h}}=97.22\frac{m}{s}$ Centripetal acceleration is given as $a=\frac{v^2}{r}$ We plug in the known values to obtain: $a=\frac{(97.22)^2}{7000}$ $a=1.35\frac{m}{s^2}$
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