Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems: 38

Answer

Please see the work below.

Work Step by Step

We know that the time of flight of the protons is given as $t=\sqrt{\frac{2y}{g}}$ We plug in the known values to obtain: $t=\sqrt{\frac{(2)(1.2\times 10^{-6})}{9.8}}$ $t=4.94\times 10^{-4}s$ The speed of the protons is $v=\frac{x}{t}$ We plug in the known values to obtain: $v=\frac{1700}{4.949\times 10^{-4}}=3.4\times 10^6\frac{m}{s}$
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