## Essential University Physics: Volume 1 (3rd Edition)

We know that the time of flight is $t=\frac{x}{v}$ $t=\frac{0.001}{12}$ $t=8.333\times 10^{-5}s$ We can find the height as $h=(\frac{1}{2})gt^2$ We plug in the known values to obtain: $h=(\frac{1}{2})(9.8)(8.333\times 10^{-5})^2=3.4\times 10^{-8}m$