Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems - Page 48: 37


Please see the work below.

Work Step by Step

We know that the time of flight is $t=\frac{x}{v}$ $t=\frac{0.001}{12}$ $t=8.333\times 10^{-5}s$ We can find the height as $h=(\frac{1}{2})gt^2$ We plug in the known values to obtain: $h=(\frac{1}{2})(9.8)(8.333\times 10^{-5})^2=3.4\times 10^{-8}m$
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