Answer
Please see the work below.
Work Step by Step
We know that
$R=\frac{v_{\circ}^2}{g}$
Hence, the range is inversely proportional to g
$\frac{R_{Moon}}{R_{Earth}}=\frac{g_{Earth}}{g_{Moon}}$
$R_{Moon}=R_{Earth}(\frac{g_{Earth}}{g_{Moon}})$
We plug in the known values to obtain:
$R_{Moon}=(180)(\frac{9.8}{1.63})=1100m$
