## Essential University Physics: Volume 1 (3rd Edition)

a) $\sqrt5A$ b) $\sqrt{10}A$
We find the magnitudes using the equation for distance: a) $d = \sqrt{(2A)^2 + A^2} =\sqrt5A$ b) $d = \sqrt{(3A)^2 + (-A)^2} =\sqrt{10}A$