Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems - Page 48: 45


a) $\sqrt5A$ b) $\sqrt{10}A$

Work Step by Step

We find the magnitudes using the equation for distance: a) $d = \sqrt{(2A)^2 + A^2} =\sqrt5A$ b) $d = \sqrt{(3A)^2 + (-A)^2} =\sqrt{10}A$
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