Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 3 - Exercises and Problems: 51

Answer

Please see the work below.

Work Step by Step

We know that $a=\frac{v^2}{r}$ This can be rearranged as $r=\frac{v^2}{a}$ We plug in the known values to obtain: $r=\frac{(19.44)^2}{3.92}=96m$
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