Answer
315 J
Work Step by Step
We find:
$w=-P\Delta V$
$=-(1.00\,atm)(1.22\,L-5.55\,L)$
$=4.33\,L\cdot atm$
$=4.33\,L\cdot atm\times\frac{101.325\,J}{1\,L\cdot atm}$
$=439\,J$
Since heat is given off, $q$ is taken as negative.
$\Delta E= q+w= (-124\,J)+(439\,J)$
$=315\,J$
