Answer
(a) $9.987\times10^{6}\,J$
(b) $9.987\times10^{3}\,kJ$
(c) 2.77 kWh
Work Step by Step
We find:
(a) $2387\,Cal=2387\,Cal\times\frac{4184\,J}{1\,Cal}$
$=9.987\times10^{6}\,J$
(b) $2387\,Cal=9.987\times10^{6}\,J$
$=9.987\times10^{6}\,J\times\frac{1\,kJ}{1000\,J}$
$=9.987\times10^{3}\,kJ$
(c) $2387\,Cal=2387\,Cal\times\frac{4184\,J}{1\,Cal}\times\frac{1\,kWh}{3.60\times10^{6}\,J}$
$=2.77\,kWh$
