Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 6 - Exercises - Page 289: 53

Answer

489 J

Work Step by Step

We find: $w=-P\Delta V$ $=-(1.0\,atm)(0.85\,L-0.10\,L)$ $=-0.75\,L\cdot atm$ $=-0.75\,L\cdot atm\times\frac{101.325\,J}{1\,L\cdot atm}$ $=-76\,J$ Since heat is absorbed, $q$ is taken as positive. $\Delta E= q+w= 565\,J+(-76\,J)$ $=489\,J$
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