Answer
(a) $2.68\times10^{9}\,J$
(b) $2.68\times10^{6}\,kJ$
(c) $6.41\times10^{5}\,Cal$
Work Step by Step
We find:
(a) $745\,kWh=745\,kWh\times\frac{3.60\times10^{6}\,J}{1\,kWh}$
$=2.68\times10^{9}\,J$
(b) $745\,kWh=2.68\times10^{9}\,J$
$=2.68\times10^{9}\,J\times\frac{1\,kJ}{1000\,J}$
$=2.68\times10^{6}\,kJ$
(c) $745\,kWh=2.68\times10^{9}\,J$
$=2.682\times10^{9}\,J\times\frac{1\,Cal}{4184\,J}$
$=6.41\times10^{5}\,Cal$
