Answer
$ 9.5\times 10^{4}\,J$
Work Step by Step
We find:
$m=1.50\times10^{3}\,g$
$c= 0.84\,J/g\cdot\,^{\circ}C$
$\Delta T= 100.0^{\circ}C-25.0^{\circ}C=75.0^{\circ}C$
$q=mc\Delta T$
$=(1.50\times10^{3}\,g)(0.84\,J/g\cdot\,^{\circ}C)(75.0^{\circ}C)$
$= 9.5\times 10^{4}\,J$
