Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 6 - Exercises - Page 289: 51

Answer

$-2.8\times10^{2}\,J$

Work Step by Step

We find: $w= -P\Delta V$ $=-(1.1\,atm)(2.5\,L-0.0\,L)$ $=-2.75\,L\cdot atm$ $=-2.75\,L\cdot atm\times\frac{101.325\,J}{1\,L\cdot atm}$ $=-2.8\times10^{2}\,J$
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