Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 6 - Exercises - Page 289: 41

Answer

-727 kJ

Work Step by Step

Since heat is released, $q$ is negative. Since work is done by the system, $w$ is also negative. $\Delta E= q+w=(-622\,kJ)+(-105\,kJ)$ $=-727\,kJ$
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