Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 6 - Exercises - Page 289: 44

Answer

-77 kJ

Work Step by Step

As heat is absorbed, $q$ is taken as positive. As work is done by the system, $w$ is taken as negative. $\Delta E=q+w= 115\,J+(-77\,kJ)$ $=0.115\,kJ-77\,kJ$ $=-77\,kJ$
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