Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Review Exercises - Page 291: 9



Work Step by Step

RECALL: $y=\cos^{-1}{x} \longrightarrow \cos{y}=x$, $y$ is in the interval $[0, \pi]$ Note that $\cos {(\frac{3\pi}{4})}=-\frac{\sqrt2}{2}$. Therefore, $y=\cos^{-1}{(-\frac{\sqrt2}{2})}\longrightarrow y=\frac{3\pi}{4}$
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