Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Review Exercises - Page 291: 8



Work Step by Step

RECALL: $y=\arcsin{x} \longrightarrow \sin{y}=x$, $y$ is in the interval $[-\frac{\pi}{2}, \frac{\pi}{2}]$ Note that $\sin {(\frac{\pi}{2})}=1$. Since sine is an odd function, $\sin{(-x)}=-\sin{x}$. Thus, $\sin{(-\frac{\pi}{2})}=-\sin{(\frac{\pi}{2})}=-1$ Therefore, $y=\arcsin{(-1)}\longrightarrow y=-\frac{\pi}{2}$
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