Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Review Exercises - Page 291: 27



Work Step by Step

RECALL: Since $\tan{x}$ and $\tan^{-1}{x}$ are inverse functions of each other, then, for all valid values of $x$, $\tan^{-1}{(\tan(x))}=x$ Thus, $\tan^{-1}{(\tan{(\frac{\pi}{4})})}=\frac{\pi}{4}$
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