Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Review Exercises - Page 291: 21

Answer

$\theta\approx 73.26^o$

Work Step by Step

RECALL: (1) $\theta = \text{arcsec}{(x)}\longrightarrow \sec{\theta}=x$ (2) $\sec{x} =\frac{1}{\cos{x}}$ This means that $\theta=\text{arcsec}(x) \\\longrightarrow \sec{\theta}=x \\\longrightarrow \cos{\theta}=\frac{1}{x}$ Thus, $\theta =\text{arcsec}(3.4723155) \\\longrightarrow\sec{\theta}=3.4723155 \\\longrightarrow \cos{\theta} = \frac{1}{3.4723155}$ Use the inverse cosine function of a scientific calculator in degree mode to obtain: $\theta = \arccos{\left(\frac{1}{3.4723155}\right)} \\\theta=73.26220613^o \\\theta\approx 73.26^o$
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