Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Review Exercises - Page 291: 5



Work Step by Step

RECALL: $y=\sin^{-1}{x} \longrightarrow \sin{y}=x$ Note that $\sin{(\frac{\pi}{4})}=\frac{\sqrt{2}}{2}$. Therefore, $y=\sin^{-1}{(\frac{\sqrt2}{2})}\longrightarrow y=\frac{\pi}{4}$
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