Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Review Exercises - Page 291: 28

Answer

$0$

Work Step by Step

RECALL: Since $\cos{x}$ and $\cos^{-1}{x}$ are inverse functions of each other, then, for all valid values of $x$, $\cos^{-1}{(\cos(x))}=x$ Thus, $\cos^{-1}{(\cos{(0)})}=0$
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