Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Review Exercises - Page 291: 10



Work Step by Step

RECALL: $y=\arctan{x} \longrightarrow \tan{y}=x$, $y$ is in the interval $(-\frac{\pi}{2}, \frac{\pi}{2})$ Note that $\tan {(\frac{\pi}{6})}=\frac{\sqrt3}{3}$. Therefore, $y=\arctan{(\frac{\sqrt3}{3})}\longrightarrow y=\frac{\pi}{6}$
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