Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Review Exercises - Page 291: 16



Work Step by Step

RECALL: $y=\tan^{-1}{(x)} \longrightarrow \tan{y}=x$, $y$ is in the interval $(-90^o, 90^o)$ Thus, $\theta=\tan^{-1}{(0)}$ implies that $\tan{\theta}=0$. Note that $\tan{(0^o)}=0$. Therefore, $\theta=\tan^{-1}{(0)}\longrightarrow \theta=0^o$
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