## Trigonometry (11th Edition) Clone

$y=-\frac{\pi}{3}$
RECALL: $y=\tan^{-1}{x} \longrightarrow \tan{y}=x$ Note that $\tan {(\frac{\pi}{3})}=\sqrt3$. Since tangent is an odd function, $\tan{(-x)}=-\tan{x}$. Thus, $\tan{(-\frac{\pi}{3})}=-\tan{(\frac{\pi}{3})}=-\sqrt3$ Therefore, $y=\tan^{-1}{(-\sqrt3)}\longrightarrow y=-\frac{\pi}{3}$