Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Review Exercises - Page 291: 14



Work Step by Step

RECALL: $y=\arccos{(x)} \longrightarrow \cos{y}=x$, $y$ is in the interval $[0^o, 90^o]$ Thus, $y=\arccos{(\frac{1}{2})}$ implies that $\cos{y}=\frac{1}{2}$. Note that $\cos{(60^o)}=\frac{1}{2}$ Therefore, $y=\arccos{(\frac{1}{2})}\longrightarrow y=60^o$
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