Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Section 8.1 - Polar Coordinates - 8.1 Exercises - Page 593: 52

Answer

$x^2+y^2=9$

Work Step by Step

So using the fact that $\sqrt {x^2+y^2}$ = r, we have$\sqrt {x^2+y^2}$ = -3. Squaring both sides we get $x^2+y^2=9$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.